MathematicsEasy74×since 2004Q3780If the points of intersections of the ellipse x216+y2b2=1{{{x^2}} \over {16}} + {{{y^2}} \over {{b^2}}} = 116x2+b2y2=1 and the circle x² + y² = 4b, b > 4 lie on the curve y² = 3x², then b is equal to :A12B10C6D5Check answerSkip