MathematicsHard202×since 2002Q5700If the points P\mathrm{P}P and Q\mathrm{Q}Q are respectively the circumcenter and the orthocentre of a △ABC\triangle \mathrm{ABC}△ABC, then PA→+PB→+PC→\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}+\overrightarrow{\mathrm{PC}}PA+PB+PC is equal to :AQP→\overrightarrow {QP}QPBPQ→\overrightarrow {PQ}PQC2PQ→2\overrightarrow {PQ}2PQD2QP→2\overrightarrow {QP}2QPCheck answerSkip