MathematicsEasy128×since 2002Q5576If the pair of straight lines x2−2pxy−y2=0{x^2} - 2pxy - {y^2} = 0x2−2pxy−y2=0 and x2−2qxy−y2=0{x^2} - 2qxy - {y^2} = 0x2−2qxy−y2=0 be such that each pair bisects the angle between the other pair, then :Apq=−1pq = -1pq=−1Bp=qp = qp=qCp=−qp = -qp=−qDpq=1pq = 1pq=1.Check answerSkip