MathematicsMedium128×since 2002Q5543If the orthocentre of the triangle, whose vertices are (1, 2), (2, 3) and (3, 1) is (α,β)(\alpha,\beta)(α,β), then the quadratic equation whose roots are α+4β\alpha+4\betaα+4β and 4α+β4\alpha+\beta4α+β, is :Ax2−20x+99=0x^2-20x+99=0x2−20x+99=0Bx2−22x+120=0x^2-22x+120=0x2−22x+120=0Cx2−19x+90=0x^2-19x+90=0x2−19x+90=0Dx2−18x+80=0x^2-18x+80=0x2−18x+80=0Check answerSkip