MathematicsMedium175×since 2002Q2671If the minimum value of f(x)=5x22+αx5,x>0f(x)=\frac{5 x^{2}}{2}+\frac{\alpha}{x^{5}}, x>0f(x)=25x2+x5α,x>0, is 14 , then the value of α\alphaα is equal to :A32B64C128D256Check answerSkip