MathematicsMedium74×since 2004Q3733If the maximum distance of normal to the ellipse x24+y2b2=1,b<2\frac{x^{2}}{4}+\frac{y^{2}}{b^{2}}=1, b < 24x2+b2y2=1,b<2, from the origin is 1, then the eccentricity of the ellipse is :A34\frac{\sqrt{3}}{4}43B12\frac{1}{2}21C12\frac{1}{\sqrt{2}}21D32\frac{\sqrt{3}}{2}23Check answerSkip