MathematicsMedium249×since 2002Q2408If the line x−23=y+12=z−1−1{{x - 2} \over 3} = {{y + 1} \over 2} = {{z - 1} \over { - 1}}3x−2=2y+1=−1z−1 intersects the plane 2x + 3y – z + 13 = 0 at a point P and the plane 3x + y + 4z = 16 at a point Q, then PQ is equal to :A272\sqrt 727B14C2142\sqrt {14}214D14\sqrt {14}14Check answerSkip