MathematicsMedium249×since 2002Q2410If the line, x−12=y+13=z−24{{x - 1} \over 2} = {{y + 1} \over 3} = {{z - 2} \over 4}2x−1=3y+1=4z−2 meets the plane, x + 2y + 3z = 15 at a point P, then the distance of P from the origin is :A52{{\sqrt 5 } \over 2}25B25\sqrt 55C9/2D7/2Check answerSkip