MathematicsMedium249×since 2002Q2462If the foot of the perpendicular drawn from (1, 9, 7) to the line passing through the point (3, 2, 1) and parallel to the planes x+2y+z=0x+2y+z=0x+2y+z=0 and 3y−z=33y-z=33y−z=3 is (α,β,γ\alpha,\beta,\gammaα,β,γ), then α+β+γ\alpha+\beta+\gammaα+β+γ is equal to :A3B1C−-−1D5Check answerSkip