MathematicsMedium249×since 2002Q2615If the equation of the plane containing the line x+2y+3z−4=0=2x+y−z+5x+2 y+3 z-4=0=2 x+y-z+5x+2y+3z−4=0=2x+y−z+5 and perpendicular to the plane r⃗=(i^−j^)+λ(i^+j^+k^)+μ(i^−2j^+3k^)\vec{r}=(\hat{i}-\hat{j})+\lambda(\hat{i}+\hat{j}+\hat{k})+\mu(\hat{i}-2 \hat{j}+3 \hat{k})r=(i^−j^)+λ(i^+j^+k^)+μ(i^−2j^+3k^) is ax+by+cz=4a x+b y+c z=4ax+by+cz=4, then (a−b+c)(a-b+c)(a−b+c) is equal to :A18B22C20D24Check answerSkip