MathematicsHard249×since 2002Q2429If the equation of plane passing through the mirror image of a point (2, 3, 1) with respect to line x+12=y−31=z+2−1{{x + 1} \over 2} = {{y - 3} \over 1} = {{z + 2} \over { - 1}}2x+1=1y−3=−1z+2 and containing the line x−23=1−y2=z+11{{x - 2} \over 3} = {{1 - y} \over 2} = {{z + 1} \over 1}3x−2=21−y=1z+1 is α\alphaαx + β\betaβy + γ\gammaγz = 24, then α\alphaα + β\betaβ + γ\gammaγ is equal to :A21B19C18D20Check answerSkip