PhysicsEasy46×since 2002Q6980If the electric flux entering and leaving an enclosed surface respectively is ϕ1{\phi _1}ϕ1 and ϕ2,{\phi _2},ϕ2, the electric charge inside the surface will beA(ϕ2−ϕ1)ε0\left( {{\phi _2} - {\phi _1}} \right){\varepsilon _0}(ϕ2−ϕ1)ε0B(ϕ2+ϕ1)/ε0\left( {{\phi _2} + {\phi _1}} \right)/{\varepsilon _0}(ϕ2+ϕ1)/ε0C(ϕ1−ϕ2)/ε0\left( {{\phi _1} - {\phi _2}} \right)/{\varepsilon _0}(ϕ1−ϕ2)/ε0D(ϕ1+ϕ2)ε0\left( {{\phi _1} + {\phi _2}} \right){\varepsilon _0}(ϕ1+ϕ2)ε0Check answerSkip