MathematicsMedium175×since 2002Q2786If the angle made by the tangent at the point (x₀, y₀) on the curve x=12(t+sintcost)x = 12(t + \sin t\cos t)x=12(t+sintcost), y=12(1+sint)2y = 12{(1 + \sin t)^2}y=12(1+sint)2, 0<t<π20 < t < {\pi \over 2}0<t<2π, with the positive x-axis is π3{\pi \over 3}3π, then y₀ is equal to:A6(3+22)6\left( {3 + 2\sqrt 2 } \right)6(3+22)B3(7+43)3\left( {7 + 4\sqrt 3 } \right)3(7+43)C27D48Check answerSkip