MathematicsMedium249×since 2002Q2487If the angle between the lines, x2=y2=z1{x \over 2} = {y \over 2} = {z \over 1}2x=2y=1z and 5−x−2=7y−14p=z−34 {{5 - x} \over { - 2}} = {{7y - 14} \over p} = {{z - 3} \over 4}\,\,−25−x=p7y−14=4z−3 is cos−1(23),{\cos ^{ - 1}}\left( {{2 \over 3}} \right),cos−1(32), then p is equal to :A72{7 \over 2}27B27{2 \over 7}72C−-− 74{7 \over 4}47D−-− 47{4 \over 7}74Check answerSkip