MathematicsMedium249×since 2002Q2392If the angle between the line x=y−12=z−3λx = {{y - 1} \over 2} = {{z - 3} \over \lambda }x=2y−1=λz−3 and the plane x+2y+3z=4x+2y+3z=4x+2y+3z=4 is cos−1(514),{\cos ^{ - 1}}\left( {\sqrt {{5 \over {14}}} } \right),cos−1(145), then λ\lambdaλ equals :A32{3 \over 2}23B25{2 \over 5}52C53{5 \over 3}35D23{2 \over 3}32Check answerSkip