PhysicsMedium56×since 2002Q6156If q_f is the free charge on the capacitor plates and q_b is the bound charge on the dielectric slab of dielectric constant k placed between the capacitor plates, then bound charge q_b an be expressed as :Aqb=qf(1−1k){q_b} = {q_f}\left( {1 - {1 \over {\sqrt k }}} \right)qb=qf(1−k1)Bqb=qf(1−1k){q_b} = {q_f}\left( {1 - {1 \over k}} \right)qb=qf(1−k1)Cqb=qf(1+1k){q_b} = {q_f}\left( {1 + {1 \over {\sqrt k }}} \right)qb=qf(1+k1)Dqb=qf(1+1k){q_b} = {q_f}\left( {1 + {1 \over k}} \right)qb=qf(1+k1)Check answerSkip