MathematicsMedium210×since 2002Q3318If ϕ(x)=1x∫π4x(42sint−3ϕ′(t))dt,x>0\phi(x)=\frac{1}{\sqrt{x}} \int\limits_{\frac{\pi}{4}}^x\left(4 \sqrt{2} \sin t-3 \phi^{\prime}(t)\right) d t, x>0ϕ(x)=x14π∫x(42sint−3ϕ′(t))dt,x>0, then ∅′(π4)\emptyset^{\prime}\left(\frac{\pi}{4}\right)∅′(4π) is equal to :A46+π\frac{4}{6+\sqrt{\pi}}6+π4B46−π\frac{4}{6-\sqrt{\pi}}6−π4C8π\frac{8}{\sqrt{\pi}}π8D86+π\frac{8}{6+\sqrt{\pi}}6+π8Check answerSkip