MathematicsMedium202×since 2002Q5737If a→ . b→=1, b→ . c→=2\overrightarrow a \,.\,\overrightarrow b = 1,\,\overrightarrow b \,.\,\overrightarrow c = 2a.b=1,b.c=2 and c→ . a→=3\overrightarrow c \,.\,\overrightarrow a = 3c.a=3, then the value of [a→×(b→×c→), b→×(c→×a→), c→×(b→×a→)]\left[ {\overrightarrow a \times \left( {\overrightarrow b \times \overrightarrow c } \right),\,\overrightarrow b \times \left( {\overrightarrow c \times \overrightarrow a } \right),\,\overrightarrow c \times \left( {\overrightarrow b \times \overrightarrow a } \right)} \right][a×(b×c),b×(c×a),c×(b×a)] is :A0B−6a→ . (b→×c→)- 6\overrightarrow a \,.\,\left( {\overrightarrow b \times \overrightarrow c } \right)−6a.(b×c)C−12c→ . (a→×b→)- 12\overrightarrow c \,.\,\left( {\overrightarrow a \times \overrightarrow b } \right)−12c.(a×b)D−12b→ . (c→×a→)- 12\overrightarrow b \,.\,\left( {\overrightarrow c \times \overrightarrow a } \right)−12b.(c×a)Check answerSkip