MathematicsHard202×since 2002Q5715If a→=110(3i^+k^)\overrightarrow a = {1 \over {\sqrt {10} }}\left( {3\widehat i + \widehat k} \right)a=101(3i+k) and b→=17(2i^+3j^−6k^),\overrightarrow b = {1 \over 7}\left( {2\widehat i + 3\widehat j - 6\widehat k} \right),b=71(2i+3j−6k), then the value of (2a→−b→)[(a→×b→)×(a→+2b→)]\left( {2\overrightarrow a - \overrightarrow b } \right)\left[ {\left( {\overrightarrow a \times \overrightarrow b } \right) \times \left( {\overrightarrow a + 2\overrightarrow b } \right)} \right](2a−b)[(a×b)×(a+2b)] is :A−3-3−3B555C333D−5-5−5Check answerSkip