MathematicsMedium178×since 2002Q5236If logea,loge b,logec\log _e \mathrm{a}, \log _e \mathrm{~b}, \log _e \mathrm{c}logea,loge b,logec are in an A.P. and logea−loge2 b,loge2 b−loge3c,loge3c−loge\log _e \mathrm{a}-\log _e 2 \mathrm{~b}, \log _e 2 \mathrm{~b}-\log _e 3 \mathrm{c}, \log _e 3 \mathrm{c} -\log _elogea−loge2 b,loge2 b−loge3c,loge3c−loge a are also in an A.P, then a:b:ca: b: ca:b:c is equal toA6:3:26: 3: 26:3:2B9:6:49: 6: 49:6:4C25:10:425: 10: 425:10:4D16:4:116: 4: 116:4:1Check answerSkip