MathematicsMedium53×since 2002Q3247If ∣z2−1∣=∣z∣2+1\,\left| {{z^2} - 1} \right| = {\left| z \right|^2} + 1z2−1=∣z∣2+1, then z lies on :Aan ellipseBthe imaginary axisCa circleDthe real axisCheck answerSkip