MathematicsEasy38×since 2002Q3569If y=y(x)y=y(x)y=y(x) is the solution of the differential equation dy dx+2y=sin(2x),y(0)=34\frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=\sin (2 x), y(0)=\frac{3}{4} dxdy+2y=sin(2x),y(0)=43, then y(π8)y\left(\frac{\pi}{8}\right)y(8π) is equal to :Ae−π/8\mathrm{e}^{-\pi / 8}e−π/8Beπ/4\mathrm{e}^{\pi / 4}eπ/4Ce−π/4\mathrm{e}^{-\pi / 4}e−π/4Deπ/8\mathrm{e}^{\pi / 8}eπ/8Check answerSkip