MathematicsMedium38×since 2002Q3642If y=y(x)y=y(x)y=y(x) is the solution curve of the differential equation (x2−4)dy−(y2−3y)dx=0,x>2,y(4)=32\left(x^2-4\right) \mathrm{d} y-\left(y^2-3 y\right) \mathrm{d} x=0, x>2, y(4)=\frac{3}{2}(x2−4)dy−(y2−3y)dx=0,x>2,y(4)=23 and the slope of the curve is never zero, then the value of y(10)y(10)y(10) equals :A31+(8)1/4\frac{3}{1+(8)^{1 / 4}}1+(8)1/43B31−(8)1/4\frac{3}{1-(8)^{1 / 4}}1−(8)1/43C31−22\frac{3}{1-2 \sqrt{2}}1−223D31+22\frac{3}{1+2 \sqrt{2}}1+223Check answerSkip