PhysicsMedium251×since 2002Q7438If n\mathrm{n}n is the number density and d\mathrm{d}d is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by :A12nπd2\frac{1}{\sqrt{2} \mathrm{n} \pi \mathrm{d}^2}2nπd21B12n2π2d2\frac{1}{\sqrt{2} n^2 \pi^2 d^2}2n2π2d21C12nπd2\frac{1}{\sqrt{2 n \pi d^2}}2nπd21D2nπd2\sqrt{2} \mathrm{n} \pi \mathrm{d}^22nπd2Check answerSkip