MathematicsHard175×since 2002Q2766If β\betaβ is one of the angles between the normals to the ellipse, x² + 3y² = 9 at the points (3 cos θ\thetaθ, 3sinθ\sqrt 3 \sin \theta3sinθ) and (−-− 3 sin θ\thetaθ, 3 cosθ\sqrt 3 \,\cos \theta3cosθ); θ∈(0,π2);\theta \in \left( {0,{\pi \over 2}} \right);θ∈(0,2π); then 2 cotβsin2θ{{2\,\cot \beta } \over {\sin 2\theta }}sin2θ2cotβ is equal to :A23{2 \over {\sqrt 3 }}32B13{1 \over {\sqrt 3 }}31C2\sqrt 22D34{{\sqrt 3 } \over 4}43Check answerSkip