MathematicsMedium210×since 2002Q3361If I1=∫01e−xcos2x dx;{I_1} = \int_0^1 {{e^{ - x}}} {\cos ^2}x{\mkern 1mu} dx;I1=∫01e−xcos2xdx; I2=∫01e−x2cos2x dx{I_2} = \int_0^1 {{e^{ - {x^2}}}} {\cos ^2}x{\mkern 1mu} dxI2=∫01e−x2cos2xdx and I3=∫01e−x3dx;{I_3} = \int_0^1 {{e^{ - {x^3}}}} dx;I3=∫01e−x3dx; thenAI₂ > I₃ > I₁BI₂ > I₁ > I₃CI₃ > I₂ > I₁DI₃ > I₁ > I₂Check answerSkip