MathematicsMedium53×since 2002Q3269If for z=α+iβ,∣z+2∣=z+4(1+i)z=\alpha+i \beta,|z+2|=z+4(1+i)z=α+iβ,∣z+2∣=z+4(1+i), then α+β\alpha+\betaα+β and αβ\alpha \betaαβ are the roots of the equation :Ax2+2x−3=0x^{2}+2 x-3=0x2+2x−3=0Bx2+3x−4=0x^{2}+3 x-4=0x2+3x−4=0Cx2+x−12=0x^{2}+x-12=0x2+x−12=0Dx2+7x+12=0x^{2}+7 x+12=0x2+7x+12=0Check answerSkip