Option A. … form using … Hospital's rule

Limits Continuity and Differentiability

JEE Main 2002 · Annual, Paper 1 · Q4220

MathematicsEasy179×since 2002Q4220

f\left( 1 \right) = 1,{f'}\left( 1 \right) = 2,

then

\mathop {\lim }\limits_{x \to 1} {{\sqrt {f\left( x \right)} - 1} \over {\sqrt x - 1}}

JEE Main 2002 · Annual, Paper 1 · Q4220

MathematicsEasy179×since 2002Q4220

f\left( 1 \right) = 1,{f'}\left( 1 \right) = 2,

then

\mathop {\lim }\limits_{x \to 1} {{\sqrt {f\left( x \right)} - 1} \over {\sqrt x - 1}}

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