MathematicsMedium57×since 2003Q3968If e₁ and e₂ are the eccentricities of the ellipse, x218+y24=1{{{x^2}} \over {18}} + {{{y^2}} \over 4} = 118x2+4y2=1 and the hyperbola, x29−y24=1{{{x^2}} \over 9} - {{{y^2}} \over 4} = 19x2−4y2=1 respectively and (e₁, e₂) is a point on the ellipse, 15x² + 3y² = k, then k is equal to :A17B16C15D14Check answerSkip