MathematicsMedium38×since 2002Q3547If dydx+2ytanx=sinx, 0<x<π2{{dy} \over {dx}} + 2y\tan x = \sin x,\,0 < x < {\pi \over 2}dxdy+2ytanx=sinx,0<x<2π and y(π3)=0y\left( {{\pi \over 3}} \right) = 0y(3π)=0, then the maximum value of y(x)y(x)y(x) is :A18{1 \over 8}81B34{3 \over 4}43C14{1 \over 4}41D38{3 \over 8}83Check answerSkip