MathematicsMedium53×since 2002Q3233If α,β∈C\alpha ,\beta \in Cα,β∈C are the distinct roots of the equation x² - x + 1 = 0, then α101+β107{\alpha ^{101}} + {\beta ^{107}}α101+β107 is equal to :A2B-1C0D1Check answerSkip