MathematicsEasy92×since 2002Q4668If a≠0a \ne 0a=0 and the line 2bx+3cy+4d=02bx+3cy+4d=02bx+3cy+4d=0 passes through the points of intersection of the parabolas y2=4ax{y^2} = 4axy2=4ax and x2=4ay{x^2} = 4ayx2=4ay, then :Ad2+(3b−2c)2=0{d^2} + {\left( {3b - 2c} \right)^2} = 0d2+(3b−2c)2=0Bd2+(3b+2c)2=0{d^2} + {\left( {3b + 2c} \right)^2} = 0d2+(3b+2c)2=0Cd2+(2b−3c)2=0{d^2} + {\left( {2b - 3c} \right)^2} = 0d2+(2b−3c)2=0Dd2+(2b+3c)2=0{d^2} + {\left( {2b + 3c} \right)^2} = 0d2+(2b+3c)2=0Check answerSkip