PhysicsHard202×since 2002Q8373If A→\overrightarrow AA and B→\overrightarrow BB are two vectors satisfying the relation A→\overrightarrow AA . B→\overrightarrow BB = ∣A→×B→∣\left| {\overrightarrow A \times \overrightarrow B } \right|A×B. Then the value of ∣A→−B→∣\left| {\overrightarrow A - \overrightarrow B } \right|A−B will be :AA2+B2+2AB\sqrt {{A^2} + {B^2} + \sqrt 2 AB}A2+B2+2ABBA2+B2\sqrt {{A^2} + {B^2}}A2+B2CA2+B2−2AB\sqrt {{A^2} + {B^2} - \sqrt 2 AB}A2+B2−2ABDA2+B2+2AB\sqrt {{A^2} + {B^2} + 2AB}A2+B2+2ABCheck answerSkip