MathematicsEasy98×since 2002Q4830If nPr=nPr+1{}^n{P_r} = {}^n{P_{r + 1}}nPr=nPr+1 and nCr=nCr−1{}^n{C_r} = {}^n{C_{r - 1}}nCr=nCr−1, then the value of r is equal to :A1B4C2D3Check answerSkip