MathematicsMedium244×since 2002Q4433If a>0a>0a>0 and discriminant of ax2+2bx+c\,a{x^2} + 2bx + cax2+2bx+c is −ve-ve−ve, then \left| {\matrix{ a & b & {ax + b} \cr b & c & {bx + c} \cr {ax + b} & {bx + c} & 0 \cr } } \right| is equal toA+ve+ve+veB(ac−b2)(ax2+2bx+c)\left( {ac - {b^2}} \right)\left( {a{x^2} + 2bx + c} \right)(ac−b2)(ax2+2bx+c)C−ve-ve−veD000Check answerSkip