MathematicsMedium210×since 2002Q3389If θ\thetaθ₁ and θ\thetaθ₂ be respectively the smallest and the largest values of θ\thetaθ in (0, 2π\piπ) - {π\piπ} which satisfy the equation, 2cot²θ\thetaθ - 5sinθ{5 \over {\sin \theta }}sinθ5 + 4 = 0, then ∫θ1θ2cos23θdθ\int\limits_{{\theta _1}}^{{\theta _2}} {{{\cos }^2}3\theta d\theta }θ1∫θ2cos23θdθ is equal to :Aπ9{\pi \over 9}9πB2π3{{2\pi } \over 3}32πCπ3{{\pi } \over 3}3πDπ3+16{\pi \over 3} + {1 \over 6}3π+61Check answerSkip