MathematicsHard115×since 2008Q4383If p,qp,qp,q and rrr are three propositions, then which of the following combination of truth values of p,qp,qp,q and rrr makes the logical expression {(p∨q)∧((∼p)∨r)}→((∼q)∨r)\left\{ {(p \vee q) \wedge \left( {( \sim p) \vee r} \right)} \right\} \to \left( {( \sim q) \vee r} \right){(p∨q)∧((∼p)∨r)}→((∼q)∨r) false?Ap=F,q=T,r=Fp = F,q = T,r = Fp=F,q=T,r=FBp=T,q=T,r=Fp = T,q = T,r = Fp=T,q=T,r=FCp=T,q=F,r=Tp = T,q = F,r = Tp=T,q=F,r=TDp=T,q=F,r=Fp = T,q = F,r = Fp=T,q=F,r=FCheck answerSkip