MathematicsMedium175×since 2002Q2631If x=−1x=-1x=−1 and x=2x=2x=2 are extreme points of f(x)=α log∣x∣+βx2+xf\left( x \right) = \alpha \,\log \left| x \right|+\beta {x^2} + xf(x)=αlog∣x∣+βx2+x thenAα=2,β=−12\alpha = 2,\beta = - {1 \over 2}α=2,β=−21Bα=2,β=12\alpha = 2,\beta = {1 \over 2}α=2,β=21Cα=−6,β=12\alpha = - 6,\beta = {1 \over 2}α=−6,β=21Dα=−6,β=−12\alpha = - 6,\beta = -{1 \over 2}α=−6,β=−21Check answerSkip