MathematicsMedium249×since 2002Q2413If an angle between the line, x+12=y−21=z−3−2{{x + 1} \over 2} = {{y - 2} \over 1} = {{z - 3} \over { - 2}}2x+1=1y−2=−2z−3 and the plane, x−2y−kz=3x - 2y - kz = 3x−2y−kz=3 is cos−1(223),{\cos ^{ - 1}}\left( {{{2\sqrt 2 } \over 3}} \right),cos−1(322), then a value of k is :A35\sqrt {{3 \over 5}}53B−52- {5 \over 2}−25C−32- {3 \over 2}−23D53\sqrt {{5 \over 3}}35Check answerSkip