MathematicsMedium179×since 2002Q4288If α=limx→π4tan3x−tanxcos(x+π4)\alpha = \mathop {\lim }\limits_{x \to {\pi \over 4}} {{{{\tan }^3}x - \tan x} \over {\cos \left( {x + {\pi \over 4}} \right)}}α=x→4πlimcos(x+4π)tan3x−tanx and β=limx→0(cosx)cotx\beta = \mathop {\lim }\limits_{x \to 0 } {(\cos x)^{\cot x}}β=x→0lim(cosx)cotx are the roots of the equation, ax² + bx −-− 4 = 0, then the ordered pair (a, b) is :A(1, −-−3)B(−-−1, 3)C(−-−1, −-−3)D(1, 3)Check answerSkip