PhysicsEasy100×since 2002Q8131If a simple harmonic motion is represented by d2xdt2+αx=0.{{{d^2}x} \over {d{t^2}}} + \alpha x = 0.dt2d2x+αx=0. its time period isA2πα{{2\pi } \over {\sqrt \alpha }}α2πB2πα{{2\pi } \over \alpha }α2πC2πα2\pi \sqrt \alpha2παD2πα2\pi \alpha2παCheck answerSkip