MathematicsMedium244×since 2002Q4524If A = \left( {\matrix{ 0 & {\sin \alpha } \cr {\sin \alpha } & 0 \cr } } \right) and det(A2−12I)=0\det \left( {{A^2} - {1 \over 2}I} \right) = 0det(A2−21I)=0, then a possible value of α\alphaα is :Aπ4{\pi \over 4}4πBπ6{\pi \over 6}6πCπ2{\pi \over 2}2πDπ3{\pi \over 3}3πCheck answerSkip