MathematicsMedium38×since 2002Q3604If a curve y = f(x), passing through the point (1, 2), is the solution of the differential equation, 2x²dy= (2xy + y²)dx, then f(12)f\left( {{1 \over 2}} \right)f(21) is equal to :A11−loge2{1 \over {1 - {{\log }_e}2}}1−loge21B11+loge2{1 \over {1 + {{\log }_e}2}}1+loge21C−11+loge2{{ - 1} \over {1 + {{\log }_e}2}}1+loge2−1D1+loge2{1 + {{\log }_e}2}1+loge2Check answerSkip