PhysicsMedium148×since 2002Q8023If 1000 droplets of water of surface tension 0.07 N/m0.07 \mathrm{~N} / \mathrm{m}0.07 N/m, having same radius 1 mm1 \mathrm{~mm}1 mm each, combine to from a single drop. In the process the released surface energy is :- (Take π=227)\left( {\mathrm{Take}\,\pi = {{22} \over 7}} \right)(Takeπ=722)A7.92×10−4 J7 .92 \times 10^{-4} \mathrm{~J}7.92×10−4 JB7.92×10−6 J7 .92 \times 10^{-6} \mathrm{~J}7.92×10−6 JC8.8×10−5 J8 .8 \times 10^{-5} \mathrm{~J}8.8×10−5 JD9.68×10−4 J9 .68 \times 10^{-4} \mathrm{~J}9.68×10−4 JCheck answerSkip