Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is …. If the curve passes through the centre of the circle x² + y² – 2x – 2y = 0, then its equation is :

Application of Derivatives

JEE Main 2019 · 8 Apr, Evening shift · Q2771

MathematicsMedium175×since 2002Q2771

Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is

2y \over x^2

. If the curve passes through the centre of the circle x² + y² – 2x – 2y = 0, then its equation is :

JEE Main 2019 · 8 Apr, Evening shift · Q2771

MathematicsMedium175×since 2002Q2771

Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is

2y \over x^2

. If the curve passes through the centre of the circle x² + y² – 2x – 2y = 0, then its equation is :