MathematicsHard175×since 2002Q2625Given P(x)=x4+ax3+bx2+cx+dP\left( x \right) = {x^4} + a{x^3} + b{x^2} + cx + dP(x)=x4+ax3+bx2+cx+d such that x=0x=0x=0 is the only real root of P′ (x)=0.P'\,\left( x \right) = 0.P′(x)=0. If P(−1)<P(1),P\left( { - 1} \right) < P\left( 1 \right),P(−1)<P(1), then in the interval [−1,1]:\left[ { - 1,1} \right]:[−1,1]:AP(−1)P(-1)P(−1) is not minimum but P(1)P(1)P(1) is the maximum of PPPBP(−1)P(-1)P(−1) is the minimum but P(1)P(1)P(1) is not the maximum of PPPCNeither P(−1)P(-1)P(−1) is the minimum nor P(1)P(1)P(1) is the maximum of PPPDP(−1)P(-1)P(−1) is the minimum and P(1)P(1)P(1) is the maximum of PPPCheck answerSkip