Given CO³⁺ + e^– … CO₂⁺ ; E^o = + 1.81 V Pb⁴⁺ + 2e^– … Pb₂⁺ ; E^o = + 1.67 V Ce⁴⁺ + e^– … Ce³⁺ ; E^o = + 1.61 V Bi³⁺ + 3e^– … Bi ; E^o = + 0.20 V Oxidizing power of the species will increase in the order :

Option D. Higher the value of Standard reduction potential of metal ion electrode, the more strong oxidizing agent is that metal ion electrode and have greater oxidising power.

Electrochemistry

JEE Main 2019 · 12 Apr, Morning shift · Q986

ChemistryEasy86×since 2002Q986

Given CO³⁺ + e^–

\to

CO₂⁺ ; E^o = + 1.81 V Pb⁴⁺ + 2e^–

\to

Pb₂⁺ ; E^o = + 1.67 V Ce⁴⁺ + e^–

\to

Ce³⁺ ; E^o = + 1.61 V Bi³⁺ + 3e^–

\to

Bi ; E^o = + 0.20 V Oxidizing power of the species will increase in the order :

Electrochemistry

JEE Main 2019 · 12 Apr, Morning shift · Q986

ChemistryEasy86×since 2002Q986

Given CO³⁺ + e^–

\to

CO₂⁺ ; E^o = + 1.81 V Pb⁴⁺ + 2e^–

\to

Pb₂⁺ ; E^o = + 1.67 V Ce⁴⁺ + e^–

\to

Ce³⁺ ; E^o = + 1.61 V Bi³⁺ + 3e^–

\to

Bi ; E^o = + 0.20 V Oxidizing power of the species will increase in the order :

Electrochemistry

More on Electrochemistry

Electrochemistry

More on Electrochemistry