PhysicsMedium159×since 2002Q7251Four particles, each of mass MMM and equidistant from each other, move along a circle of radius RRR under the action of their mutual gravitational attraction. The speed of each particle is :AGMR\sqrt {{{GM} \over R}}RGMB22GMR\sqrt {2\sqrt 2 {{GM} \over R}}22RGMCGMR(1+22)\sqrt {{{GM} \over R}\left( {1 + 2\sqrt 2 } \right)}RGM(1+22)D12GMR(1+22){1 \over 2}\sqrt {{{GM} \over R}\left( {1 + 2\sqrt 2 } \right)}21RGM(1+22)Check answerSkip