MathematicsHard64×since 2002Q2938For two positive real numbers a and b such that 1a2+1b3=4{1 \over {{a^2}}} + {1 \over {{b^3}}} = 4a21+b31=4, then minimum value of the constant term in the expansion of (ax18+bx−112)10{\left( {a{x^{{1 \over 8}}} + b{x^{ - {1 \over {12}}}}} \right)^{10}}(ax81+bx−121)10 is :A1052{{105} \over 2}2105B1054{{105} \over 4}4105C1058{{105} \over 8}8105D10516{{105} \over 16}16105Check answerSkip