MathematicsMedium244×since 2002Q4619For α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R, suppose the system of linear equations x−y+z=52x+2y+αz=83x−y+4z=β\begin{aligned} & x-y+z=5 \\ & 2 x+2 y+\alpha z=8 \\ & 3 x-y+4 z=\beta \end{aligned}x−y+z=52x+2y+αz=83x−y+4z=β has infinitely many solutions. Then α\alphaα and β\betaβ are the roots of :Ax2+18x+56=0x^2+18 x+56=0x2+18x+56=0Bx2−10x+16=0x^2-10 x+16=0x2−10x+16=0Cx2+14x+24=0x^2+14 x+24=0x2+14x+24=0Dx2−18x+56=0x^2-18 x+56=0x2−18x+56=0Check answerSkip